Algebra-1 Problems
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8.2 Substituting for a Variable |
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Problem # |
Problem Statement |
Problems Similar To |
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1. |
Solve using substitution method. |
\begin{equation}y=4x\textrm{ },\textrm{ }5x+6y=6\end{equation} |
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2. |
Solve using substitution method. |
\begin{equation}6x+y=5\textrm{ },\textrm{ }8x-6y=4\end{equation} |
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3. |
Solve using substitution method. |
\begin{equation}x=5-5y\textrm{ },\textrm{ }5x-4y=9\end{equation} |
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4. |
Solve using substitution method. |
\begin{equation}8x+6y=0\textrm{ },\textrm{ }2x+y=-5\end{equation} |
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5. |
Solve using substitution method. |
\begin{equation}-x+6y=-8\textrm{ },\textrm{ }7x+y=5\end{equation} |
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6. |
Solve using substitution method. |
\begin{equation}3x-y=-4\textrm{ },\textrm{ }8x-10y=-4\end{equation} |
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7. |
Solve using substitution method. |
\begin{equation}-x+9y=-8\textrm{ },\textrm{ }5x-10y=4\end{equation} |
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8. |
Solve using substitution method. |
\begin{equation}4x+4y=-28\textrm{ },\textrm{ }7x-y=-7\end{equation} |
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9. |
Solve using substitution method. |
\begin{equation}7x+7y=49\textrm{ },\textrm{ }(-2)x+2y=-6\end{equation} |
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10. |
Solve using substitution method. |
\begin{equation}5x+7y=7\textrm{ },\textrm{ }-35x+50y=-20\end{equation} |
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11. |
Solve using substitution method. |
\begin{equation}63x-7y=-21\textrm{ },\textrm{ }2x-10y=-10\end{equation} |
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12. |
Solve using substitution method. |
\begin{equation}y=x-10\textrm{ },\textrm{ }y=4x+3\end{equation} |
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13. |
Solve using substitution method. |
\begin{equation}y=4x+3\textrm{ },\textrm{ }y=10x-2\end{equation} |
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14. |
Solve using substitution method. |
\begin{equation}10x-y=2\textrm{ },\textrm{ }x+y=-4\end{equation} |
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15. |
Solve using substitution method. |
\begin{equation}10x+y=4\textrm{ },\textrm{ }y=x-7\end{equation} |
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16. |
Solve using substitution method. |
\begin{equation}10x+10y=0\textrm{ },\textrm{ }x+5y=-4\end{equation} |
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17. |
Solve using substitution method. |
\begin{equation}3x-5y=2\textrm{ },\textrm{ }x+7y=-5\end{equation} |
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18. |
Solve using substitution method. |
\begin{equation}(-6)x+y=0\textrm{ },\textrm{ }7x+5y=-3\end{equation} |
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19. |
Solve using substitution method. |
\begin{equation}\frac{1}{3} \times x+\frac{1}{4} \times y=6\textrm{ },\textrm{ }\frac{1}{6} \times x+y=6\end{equation} |