Algebra-1 Problems
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8.2 Substituting for a Variable |
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Problem # |
Problem Statement |
Problems Similar To |
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1. |
Solve using substitution method. |
\begin{equation}y=6x\textrm{ },\textrm{ }9x+10y=10\end{equation} |
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2. |
Solve using substitution method. |
\begin{equation}10x+y=8\textrm{ },\textrm{ }6x-9y=10\end{equation} |
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3. |
Solve using substitution method. |
\begin{equation}x=4-8y\textrm{ },\textrm{ }2x-7y=7\end{equation} |
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4. |
Solve using substitution method. |
\begin{equation}8x+2y=0\textrm{ },\textrm{ }8x+y=-2\end{equation} |
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5. |
Solve using substitution method. |
\begin{equation}-x+6y=-9\textrm{ },\textrm{ }8x+y=2\end{equation} |
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6. |
Solve using substitution method. |
\begin{equation}6x-y=-7\textrm{ },\textrm{ }8x-9y=-4\end{equation} |
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7. |
Solve using substitution method. |
\begin{equation}-x+10y=-4\textrm{ },\textrm{ }7x-2y=8\end{equation} |
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8. |
Solve using substitution method. |
\begin{equation}2x+2y=-4\textrm{ },\textrm{ }4x-y=-5\end{equation} |
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9. |
Solve using substitution method. |
\begin{equation}4x+4y=20\textrm{ },\textrm{ }(-6)x+9y=-6\end{equation} |
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10. |
Solve using substitution method. |
\begin{equation}7x+5y=3\textrm{ },\textrm{ }-15x+18y=-30\end{equation} |
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11. |
Solve using substitution method. |
\begin{equation}40x-4y=-36\textrm{ },\textrm{ }8x-6y=-8\end{equation} |
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12. |
Solve using substitution method. |
\begin{equation}y=x-2\textrm{ },\textrm{ }y=10x+9\end{equation} |
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13. |
Solve using substitution method. |
\begin{equation}y=2x+10\textrm{ },\textrm{ }y=2x-2\end{equation} |
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14. |
Solve using substitution method. |
\begin{equation}5x-y=6\textrm{ },\textrm{ }x+y=-6\end{equation} |
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15. |
Solve using substitution method. |
\begin{equation}10x+y=4\textrm{ },\textrm{ }y=x-5\end{equation} |
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16. |
Solve using substitution method. |
\begin{equation}4x+6y=0\textrm{ },\textrm{ }x+5y=-4\end{equation} |
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17. |
Solve using substitution method. |
\begin{equation}9x-9y=7\textrm{ },\textrm{ }x+2y=-7\end{equation} |
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18. |
Solve using substitution method. |
\begin{equation}(-2)x+y=0\textrm{ },\textrm{ }3x+4y=-4\end{equation} |
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19. |
Solve using substitution method. |
\begin{equation}\frac{1}{3} \times x+\frac{1}{3} \times y=4\textrm{ },\textrm{ }\frac{1}{6} \times x+y=9\end{equation} |