Algebra-1 Problems

8.2 Substituting for a Variable


Problem #

Problem Statement

Problems Similar To

1.

Solve using substitution method.

\begin{equation}y=6x\textrm{ },\textrm{ }7x+3y=6\end{equation}

2.

Solve using substitution method.

\begin{equation}8x+y=2\textrm{ },\textrm{ }7x-2y=4\end{equation}

3.

Solve using substitution method.

\begin{equation}x=2-4y\textrm{ },\textrm{ }2x-9y=9\end{equation}

4.

Solve using substitution method.

\begin{equation}5x+8y=0\textrm{ },\textrm{ }8x+y=-8\end{equation}

5.

Solve using substitution method.

\begin{equation}-x+10y=-7\textrm{ },\textrm{ }7x+y=6\end{equation}

6.

Solve using substitution method.

\begin{equation}3x-y=-4\textrm{ },\textrm{ }4x-5y=-9\end{equation}

7.

Solve using substitution method.

\begin{equation}-x+6y=-2\textrm{ },\textrm{ }3x-8y=8\end{equation}

8.

Solve using substitution method.

\begin{equation}7x+7y=-21\textrm{ },\textrm{ }7x-y=-5\end{equation}

9.

Solve using substitution method.

\begin{equation}3x+3y=21\textrm{ },\textrm{ }(-9)x+7y=-6\end{equation}

10.

Solve using substitution method.

\begin{equation}8x+4y=5\textrm{ },\textrm{ }-64x+24y=-56\end{equation}

11.

Solve using substitution method.

\begin{equation}10x-2y=-14\textrm{ },\textrm{ }9x-2y=-2\end{equation}

12.

Solve using substitution method.

\begin{equation}y=x-2\textrm{ },\textrm{ }y=9x+8\end{equation}

13.

Solve using substitution method.

\begin{equation}y=3x+6\textrm{ },\textrm{ }y=5x-9\end{equation}

14.

Solve using substitution method.

\begin{equation}5x-y=5\textrm{ },\textrm{ }x+y=-2\end{equation}

15.

Solve using substitution method.

\begin{equation}7x+y=10\textrm{ },\textrm{ }y=x-9\end{equation}

16.

Solve using substitution method.

\begin{equation}3x+5y=0\textrm{ },\textrm{ }x+3y=-5\end{equation}

17.

Solve using substitution method.

\begin{equation}9x-3y=4\textrm{ },\textrm{ }x+2y=-6\end{equation}

18.

Solve using substitution method.

\begin{equation}(-2)x+y=0\textrm{ },\textrm{ }10x+8y=-10\end{equation}

19.

Solve using substitution method.

\begin{equation}\frac{1}{3} \times x+\frac{1}{4} \times y=7\textrm{ },\textrm{ }\frac{1}{6} \times x+y=10\end{equation}