Algebra-1 Problems
|
|
8.2 Substituting for a Variable |
|
|
|
Problem # |
Problem Statement |
Problems Similar To |
|---|---|---|
|
1. |
Solve using substitution method. |
\begin{equation}y=10x\textrm{ },\textrm{ }4x+2y=7\end{equation} |
|
2. |
Solve using substitution method. |
\begin{equation}9x+y=10\textrm{ },\textrm{ }10x-9y=3\end{equation} |
|
3. |
Solve using substitution method. |
\begin{equation}x=6-7y\textrm{ },\textrm{ }8x-2y=6\end{equation} |
|
4. |
Solve using substitution method. |
\begin{equation}9x+9y=0\textrm{ },\textrm{ }2x+y=-8\end{equation} |
|
5. |
Solve using substitution method. |
\begin{equation}-x+2y=-4\textrm{ },\textrm{ }4x+y=7\end{equation} |
|
6. |
Solve using substitution method. |
\begin{equation}2x-y=-9\textrm{ },\textrm{ }10x-7y=-7\end{equation} |
|
7. |
Solve using substitution method. |
\begin{equation}-x+5y=-8\textrm{ },\textrm{ }7x-10y=10\end{equation} |
|
8. |
Solve using substitution method. |
\begin{equation}2x+2y=-8\textrm{ },\textrm{ }6x-y=-8\end{equation} |
|
9. |
Solve using substitution method. |
\begin{equation}10x+10y=30\textrm{ },\textrm{ }(-4)x+2y=-2\end{equation} |
|
10. |
Solve using substitution method. |
\begin{equation}6x+2y=7\textrm{ },\textrm{ }-28x+12y=-8\end{equation} |
|
11. |
Solve using substitution method. |
\begin{equation}10x-5y=-25\textrm{ },\textrm{ }10x-3y=-8\end{equation} |
|
12. |
Solve using substitution method. |
\begin{equation}y=x-10\textrm{ },\textrm{ }y=7x+8\end{equation} |
|
13. |
Solve using substitution method. |
\begin{equation}y=4x+3\textrm{ },\textrm{ }y=8x-2\end{equation} |
|
14. |
Solve using substitution method. |
\begin{equation}4x-y=3\textrm{ },\textrm{ }x+y=-6\end{equation} |
|
15. |
Solve using substitution method. |
\begin{equation}5x+y=9\textrm{ },\textrm{ }y=x-5\end{equation} |
|
16. |
Solve using substitution method. |
\begin{equation}2x+6y=0\textrm{ },\textrm{ }x+2y=-7\end{equation} |
|
17. |
Solve using substitution method. |
\begin{equation}3x-3y=2\textrm{ },\textrm{ }x+3y=-10\end{equation} |
|
18. |
Solve using substitution method. |
\begin{equation}(-3)x+y=0\textrm{ },\textrm{ }3x+10y=-9\end{equation} |
|
19. |
Solve using substitution method. |
\begin{equation}\frac{1}{3} \times x+\frac{1}{2} \times y=7\textrm{ },\textrm{ }\frac{1}{6} \times x+y=8\end{equation} |