Algebra-1 Problems
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8.2 Substituting for a Variable |
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Problem # |
Problem Statement |
Problems Similar To |
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1. |
Solve using substitution method. |
\begin{equation}y=6x\textrm{ },\textrm{ }7x+3y=6\end{equation} |
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2. |
Solve using substitution method. |
\begin{equation}8x+y=2\textrm{ },\textrm{ }7x-2y=4\end{equation} |
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3. |
Solve using substitution method. |
\begin{equation}x=2-4y\textrm{ },\textrm{ }2x-9y=9\end{equation} |
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4. |
Solve using substitution method. |
\begin{equation}5x+8y=0\textrm{ },\textrm{ }8x+y=-8\end{equation} |
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5. |
Solve using substitution method. |
\begin{equation}-x+10y=-7\textrm{ },\textrm{ }7x+y=6\end{equation} |
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6. |
Solve using substitution method. |
\begin{equation}3x-y=-4\textrm{ },\textrm{ }4x-5y=-9\end{equation} |
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7. |
Solve using substitution method. |
\begin{equation}-x+6y=-2\textrm{ },\textrm{ }3x-8y=8\end{equation} |
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8. |
Solve using substitution method. |
\begin{equation}7x+7y=-21\textrm{ },\textrm{ }7x-y=-5\end{equation} |
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9. |
Solve using substitution method. |
\begin{equation}3x+3y=21\textrm{ },\textrm{ }(-9)x+7y=-6\end{equation} |
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10. |
Solve using substitution method. |
\begin{equation}8x+4y=5\textrm{ },\textrm{ }-64x+24y=-56\end{equation} |
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11. |
Solve using substitution method. |
\begin{equation}10x-2y=-14\textrm{ },\textrm{ }9x-2y=-2\end{equation} |
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12. |
Solve using substitution method. |
\begin{equation}y=x-2\textrm{ },\textrm{ }y=9x+8\end{equation} |
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13. |
Solve using substitution method. |
\begin{equation}y=3x+6\textrm{ },\textrm{ }y=5x-9\end{equation} |
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14. |
Solve using substitution method. |
\begin{equation}5x-y=5\textrm{ },\textrm{ }x+y=-2\end{equation} |
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15. |
Solve using substitution method. |
\begin{equation}7x+y=10\textrm{ },\textrm{ }y=x-9\end{equation} |
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16. |
Solve using substitution method. |
\begin{equation}3x+5y=0\textrm{ },\textrm{ }x+3y=-5\end{equation} |
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17. |
Solve using substitution method. |
\begin{equation}9x-3y=4\textrm{ },\textrm{ }x+2y=-6\end{equation} |
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18. |
Solve using substitution method. |
\begin{equation}(-2)x+y=0\textrm{ },\textrm{ }10x+8y=-10\end{equation} |
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19. |
Solve using substitution method. |
\begin{equation}\frac{1}{3} \times x+\frac{1}{4} \times y=7\textrm{ },\textrm{ }\frac{1}{6} \times x+y=10\end{equation} |