Algebra-1 Problems
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8.2 Substituting for a Variable |
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Problem # |
Problem Statement |
Problems Similar To |
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1. |
Solve using substitution method. |
\begin{equation}y=7x\textrm{ },\textrm{ }2x+3y=4\end{equation} |
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2. |
Solve using substitution method. |
\begin{equation}4x+y=4\textrm{ },\textrm{ }9x-5y=8\end{equation} |
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3. |
Solve using substitution method. |
\begin{equation}x=7-5y\textrm{ },\textrm{ }5x-9y=4\end{equation} |
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4. |
Solve using substitution method. |
\begin{equation}9x+2y=0\textrm{ },\textrm{ }3x+y=-9\end{equation} |
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5. |
Solve using substitution method. |
\begin{equation}-x+9y=-5\textrm{ },\textrm{ }10x+y=2\end{equation} |
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6. |
Solve using substitution method. |
\begin{equation}10x-y=-4\textrm{ },\textrm{ }10x-6y=-3\end{equation} |
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7. |
Solve using substitution method. |
\begin{equation}-x+3y=-6\textrm{ },\textrm{ }8x-8y=2\end{equation} |
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8. |
Solve using substitution method. |
\begin{equation}6x+6y=-12\textrm{ },\textrm{ }3x-y=-2\end{equation} |
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9. |
Solve using substitution method. |
\begin{equation}7x+7y=14\textrm{ },\textrm{ }(-8)x+3y=-6\end{equation} |
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10. |
Solve using substitution method. |
\begin{equation}7x+10y=8\textrm{ },\textrm{ }-18x+18y=-12\end{equation} |
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11. |
Solve using substitution method. |
\begin{equation}100x-10y=-100\textrm{ },\textrm{ }8x-9y=-2\end{equation} |
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12. |
Solve using substitution method. |
\begin{equation}y=x-4\textrm{ },\textrm{ }y=4x+7\end{equation} |
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13. |
Solve using substitution method. |
\begin{equation}y=10x+7\textrm{ },\textrm{ }y=2x-5\end{equation} |
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14. |
Solve using substitution method. |
\begin{equation}7x-y=9\textrm{ },\textrm{ }x+y=-7\end{equation} |
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15. |
Solve using substitution method. |
\begin{equation}8x+y=4\textrm{ },\textrm{ }y=x-8\end{equation} |
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16. |
Solve using substitution method. |
\begin{equation}9x+10y=0\textrm{ },\textrm{ }x+2y=-4\end{equation} |
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17. |
Solve using substitution method. |
\begin{equation}10x-9y=3\textrm{ },\textrm{ }x+4y=-6\end{equation} |
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18. |
Solve using substitution method. |
\begin{equation}(-7)x+y=0\textrm{ },\textrm{ }10x+4y=-8\end{equation} |
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19. |
Solve using substitution method. |
\begin{equation}\frac{1}{3} \times x+\frac{1}{2} \times y=4\textrm{ },\textrm{ }\frac{1}{6} \times x+y=6\end{equation} |