Algebra-1 Problems

8.2 Substituting for a Variable


Problem #

Problem Statement

Problems Similar To

1.

Solve using substitution method.

\begin{equation}y=8x\textrm{ },\textrm{ }4x+9y=6\end{equation}

2.

Solve using substitution method.

\begin{equation}10x+y=4\textrm{ },\textrm{ }8x-9y=3\end{equation}

3.

Solve using substitution method.

\begin{equation}x=9-3y\textrm{ },\textrm{ }6x-4y=4\end{equation}

4.

Solve using substitution method.

\begin{equation}3x+2y=0\textrm{ },\textrm{ }3x+y=-3\end{equation}

5.

Solve using substitution method.

\begin{equation}-x+3y=-2\textrm{ },\textrm{ }4x+y=5\end{equation}

6.

Solve using substitution method.

\begin{equation}4x-y=-4\textrm{ },\textrm{ }5x-7y=-5\end{equation}

7.

Solve using substitution method.

\begin{equation}-x+5y=-3\textrm{ },\textrm{ }9x-2y=5\end{equation}

8.

Solve using substitution method.

\begin{equation}10x+10y=-100\textrm{ },\textrm{ }8x-y=-3\end{equation}

9.

Solve using substitution method.

\begin{equation}2x+2y=10\textrm{ },\textrm{ }(-3)x+3y=-4\end{equation}

10.

Solve using substitution method.

\begin{equation}6x+7y=7\textrm{ },\textrm{ }-21x+30y=-12\end{equation}

11.

Solve using substitution method.

\begin{equation}80x-8y=-24\textrm{ },\textrm{ }5x-5y=-7\end{equation}

12.

Solve using substitution method.

\begin{equation}y=x-3\textrm{ },\textrm{ }y=4x+6\end{equation}

13.

Solve using substitution method.

\begin{equation}y=6x+5\textrm{ },\textrm{ }y=3x-3\end{equation}

14.

Solve using substitution method.

\begin{equation}7x-y=4\textrm{ },\textrm{ }x+y=-8\end{equation}

15.

Solve using substitution method.

\begin{equation}4x+y=7\textrm{ },\textrm{ }y=x-9\end{equation}

16.

Solve using substitution method.

\begin{equation}2x+3y=0\textrm{ },\textrm{ }x+8y=-9\end{equation}

17.

Solve using substitution method.

\begin{equation}9x-2y=6\textrm{ },\textrm{ }x+6y=-5\end{equation}

18.

Solve using substitution method.

\begin{equation}(-8)x+y=0\textrm{ },\textrm{ }9x+7y=-2\end{equation}

19.

Solve using substitution method.

\begin{equation}\frac{1}{4} \times x+\frac{1}{2} \times y=10\textrm{ },\textrm{ }\frac{1}{8} \times x+y=10\end{equation}