### Algebra-1 Problems

Problem # |
Problem Statement |
Problems Similar To |
---|---|---|

1. |
Solve for x |
\begin{equation}\frac{x}{7}=\frac{\frac{12}{7}}{6}\end{equation} |

2. |
Solve for x |
\begin{equation}\frac{x}{40}=\frac{1}{4}\end{equation} |

3. |
Solve for x |
\begin{equation}\frac{1}{2}=\frac{1}{x}\end{equation} |

4. |
Solve for x |
\begin{equation}\frac{\frac{256}{3}}{8}=\frac{8x}{6}\end{equation} |

5. |
Solve for x |
\begin{equation}\frac{\frac{9}{2}}{x}=\frac{9}{x+9}\end{equation} |

6. |
Solve for x |
\begin{equation}\frac{1}{\frac{11}{3}}=\frac{x}{x+8}\end{equation} |

7. |
Solve for x |
\begin{equation}\frac{4-x}{10}=\frac{4}{40}\end{equation} |

8. |
Solve for x |
\begin{equation}\frac{x}{3}=\frac{\frac{10}{10}}{\frac{5}{10}}\end{equation} |

9. |
Solve for x |
\begin{equation}\frac{x}{5}=\frac{\frac{9}{10}}{\frac{5}{10}}\end{equation} |

10. |
If a car moving at constant speed travels 80 miles in 2 hours, how many miles will it travel in 8 hours? |
\begin{equation}\frac{80}{2}=\frac{x}{8}\end{equation} |

11. |
You work in a local mail-room at a college. One of your duties is to sort local mail from all of the other mail. You can sort 16 pieces of mail in 8 seconds. How many pieces of mail should you be able to sort in 5 minutes? |
\begin{equation}\frac{16}{8}=\frac{x}{5 \times 60}\end{equation} |

12. |
An architectural firm makes a model of a science center they are building. The ratio of the model to the actual size is 1 inch : 11 ft. Estimate the height of the building whose model is 37/11 inches tall. |
\begin{equation}\frac{1}{11}=\frac{\frac{37}{11}}{x}\end{equation} |

13. |
The scale of a map of State X shows that 1 cm represents 15 miles. The actual distance from City A to City B is 120 miles. On the map, how many centimeters are between the two Cities? |
\begin{equation}\frac{1}{15}=\frac{x}{120}\end{equation} |

14. |
The utility worker is 5 ft tall and is casting a shadow 10 ft long. At the same time, a nearby utility pole casts a shadow 16 ft long. Write and solve a proportion to find the height of the utility pole. |
\begin{equation}\frac{5}{10}=\frac{x}{16}\end{equation} |

15. |
A rectangle has an area of 8 sq in. Every dimension of the rectangle is multiplied by a scale factor, and the new rectangle has an area of 72 sq in. What was the scale factor? |
\begin{equation}8x^{2}=72\end{equation} |