Algebra-1 Problems

3.5 Variables/Parentheses on Both Sides of the Equation


Problem #

Problem Statement

Problems Similar To

1.

Solve for x

\begin{equation}\frac{15}{2} \times x=7+4x\end{equation}

2.

Solve for x

\begin{equation}2x+42=7x+7\end{equation}

3.

Solve for x

\begin{equation}4x+7-6x=x-8\end{equation}

4.

Solve for x

\begin{equation}7x-6=7x-6\end{equation}

5.

Solve for x

\begin{equation}(-4)x+23=5x-4\end{equation}

6.

Solve for x

\begin{equation}9(10x-6)=\frac{423}{5} \times x\end{equation}

7.

Solve for x

\begin{equation}7x+4(9x+5)=\frac{139}{3} \times x\end{equation}

8.

Solve for x

\begin{equation}7x+6-6x=\frac{4}{5} \times (x+9)\end{equation}

9.

Solve for x

\begin{equation}\frac{44}{7} \times (x+4)=6(x+3)+8\end{equation}

10.

Solve for x

\begin{equation}\frac{1}{9} \times x+\frac{6}{9}=\frac{10}{9}\end{equation}

11.

Solve for x

\begin{equation}\frac{1}{6} \times x+\frac{1}{2}=\frac{\frac{40}{3}}{10}\end{equation}

12.

Solve for x

\begin{equation}\frac{3}{6} \times x+\frac{16}{5}=\frac{3}{10} \times x+4\end{equation}